2x^2-3y^2=5xy

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Solution for 2x^2-3y^2=5xy equation:


Simplifying
2x2 + -3y2 = 5xy

Solving
2x2 + -3y2 = 5xy

Solving for variable 'x'.

Reorder the terms:
-5xy + 2x2 + -3y2 = 5xy + -5xy

Combine like terms: 5xy + -5xy = 0
-5xy + 2x2 + -3y2 = 0

Factor a trinomial.
(x + -3y)(2x + y) = 0

Subproblem 1

Set the factor '(x + -3y)' equal to zero and attempt to solve: Simplifying x + -3y = 0 Solving x + -3y = 0 Move all terms containing x to the left, all other terms to the right. Add '3y' to each side of the equation. x + -3y + 3y = 0 + 3y Combine like terms: -3y + 3y = 0 x + 0 = 0 + 3y x = 0 + 3y Remove the zero: x = 3y Simplifying x = 3y

Subproblem 2

Set the factor '(2x + y)' equal to zero and attempt to solve: Simplifying 2x + y = 0 Solving 2x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. 2x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 2x + 0 = 0 + -1y 2x = 0 + -1y Remove the zero: 2x = -1y Divide each side by '2'. x = -0.5y Simplifying x = -0.5y

Solution

x = {3y, -0.5y}

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